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3.4x^2+6.6x-2.2=0
a = 3.4; b = 6.6; c = -2.2;
Δ = b2-4ac
Δ = 6.62-4·3.4·(-2.2)
Δ = 73.48
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6.6)-\sqrt{73.48}}{2*3.4}=\frac{-6.6-\sqrt{73.48}}{6.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6.6)+\sqrt{73.48}}{2*3.4}=\frac{-6.6+\sqrt{73.48}}{6.8} $
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